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Mathematics
Dallas Johns
14 February, 01:17
x/5-2=x/2+3 solve for x
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Alivia Lindsey
14 February, 02:10
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Solve for x:x/5 - 2 = x/2 + 3
Put each term in x/5 - 2 over the common denominator 5: x/5 - 2 = x/5 - (10) / 5:x/5 - (10) / 5 = x/2 + 3
x/5 - (10) / 5 = (x - 10) / 5: (x - 10) / 5 = x/2 + 3
Put each term in x/2 + 3 over the common denominator 2: x/2 + 3 = x/2 + 6/2: (x - 10) / 5 = x/2 + 6/2
x/2 + 6/2 = (x + 6) / 2: (x - 10) / 5 = (x + 6) / 2
Multiply both sides by 10: (10 (x - 10)) / 5 = (10 (x + 6)) / 2
10/5 = (5*2) / 5 = 2:2 (x - 10) = (10 (x + 6)) / 2
10/2 = (2*5) / 2 = 5:2 (x - 10) = 5 (x + 6)
Expand out terms of the left hand side:2 x - 20 = 5 (x + 6)
Expand out terms of the right hand side:2 x - 20 = 5 x + 30
Subtract 5 x from both sides: (2 x - 5 x) - 20 = (5 x - 5 x) + 30
2 x - 5 x = - 3 x:-3 x - 20 = (5 x - 5 x) + 30
5 x - 5 x = 0:-3 x - 20 = 30
Add 20 to both sides: (20 - 20) - 3 x = 20 + 30
20 - 20 = 0:-3 x = 30 + 20
30 + 20 = 50:-3 x = 50
Divide both sides of - 3 x = 50 by - 3: (-3 x) / (-3) = 50 / (-3)
(-3) / (-3) = 1:x = 50 / (-3)
Multiply numerator and denominator of 50 / (-3) by - 1:Answer: x = (-50) / 3
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