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9 July, 23:27

Write each of the numbers 1,8,27, and 125 as a base raised to the 3rd power. 1 = [ ]³ 8 = [ ]³ 27 = [ ]³ 64 = [ ]³ 125 = [ ]³

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  1. 9 July, 23:49
    0
    This is what goes in the boxes

    1, 2, 3, 4, 5
  2. 10 July, 02:06
    0
    1=1^3

    8=2^3

    27=3^3

    64=4^3

    125=5^3

    These are all perfect cubes. 1^3 is the same as 1*1*1. The question is asking you to find which number, when multiplied by itself 3 times results in the given number.
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