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16 July, 06:35

Which number supports the given conjecture?

If a number is divisible by both 2 and 3, then the number is also divisible by 6.

A.

16

B.

23

C.

27

D.

36

+3
Answers (2)
  1. 16 July, 07:29
    0
    A. 16 is divisible by 2 but not divisible by 3

    B. 23 is not divisible neither by 2 nor 3

    C. 27 is not divisible by 2, however it's divisible by 3

    D. 36 is divisible both by 2 and 3

    So the only number we can focus on is 36:

    36 : 2 = 18

    36 : 3 = 12

    36 : 6 = 6

    Answer: D, 36 supports the given conjecture.
  2. 16 July, 09:52
    0
    D. 36 because 36 / 2 = 18 36 / 3 = 12 36 / 6 = 6
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