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19 February, 00:39

Solve 5^x=81. 2

Round to the nearest ten-thousandth.

X≈?

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Answers (1)
  1. 19 February, 03:47
    0
    Is that 5^x=81.2?

    5^x=81.2 take the natural log of both sides

    xln5=ln81.2 divide both sides by ln5

    x=ln81.2/ln5

    x≈2.7320 (to nearest ten-thousandth)

    If you just meant 5^x=81, the process is the same

    5^x=81 take the natural log of both sides

    xln5=ln81 divide both sides by ln5

    x=ln81/ln5

    x≈2.7304 (to nearest ten-thousandth)
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