Solve the system of equations.

4x-9y - 2=0

12x-5y+38=0

x equals?

y equals?

I: 4x-9y-2=0

II: 12x-5y+38=0

start by eliminating x by multiplying the first equation by 3 and subtracting II:

3 * (4x-9y-2) - (12-5y+38) = 3 * (0) - 0

12x-27y-6-12x+5y-38=0

-22y-44=0

-44=22y

-2=y

-> insert y=-2 in I:

4x-9 * (-2) - 2=0

4x+18-2=0

4x+16=0

4x=-16

x=-4

so the solution is y=-2 and x=-4