A rectangle is placed around a semicircle as shown below. the width of the rectangle is 6ft. find the area of the shaded region. use the value 3.14 for π, and do not round your answer. be sure to include the correct unit in your answer.

As the figure is missing, I will do the most logical assumptions and explain the way to solve the problem.

Assumptions:

1) radius of the semicircle = width of the rectangle = 6ft

2) length of the rectangle = 2*radius of the semicircle = 12 ft

3) Area of the shaded region = area of the rectangle - area of the semicircle

Solution

area of the rectangle = width * length = 6 ft * 12 ft = 72 ft^2

area of the semicircle = [1/2]*π * (r^2) = [1/2]*3.14 * (6ft) ^2 = 56.52 ft^2

area of the shaded region = 72 ft^2 - 56.52 ft^2 = 15.48ft^2

Answer: 15.48 ft^2