Four consecutive multiples of 6 yield a sum of 156. What are these multiples?

Let x be the first number:

1st number: = x

2nd consecutive multiple of 6 = x+6

3rd consecutive multiple of 6 = x+12

4rth consecutive multiple of 6 = x+18

Their sum = 156 → x + (x+6) + (x+12) + (x+18) = 156

4x + 30 = 156

4x = 120 and x = 30

The numbers are: 30,36,42,48