Can someone show me the work for this?

Suppose y = sqrt (2x + 1) where x and y are functions of t.?

suppose y = sqrt (2x + 1), where x and y are functions of t.

(a) If dx/dt = 3, find dy/dt when x = 4.

dy / dt = ?

(b) If dy/dt = 5, find dx/dt when x = 12.

dx/dt = ?

We are given the equation or function y = sqrt (2x + 1). The derivative of the equation is expressed as

1. dy/dt = 0.5 * 2 * (2x + 1) ^-0.5 dx/dt

when x = 4 and dx/dt = 3

dy/dt = 0.5 * 2 * 3 * (2*4 + 1) ^-0.5

dy/dt = 1

2. dy/dt = 0.5 * 2 * (2x + 1) ^-0.5 dx/dt

If dy/dt = 5, find dx/dt when x = 12.

5 = 0.5 * 2 (2*12 + 1) ^-0.5 dx/dt

dx/dt = 1