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23 June, 17:13

How do you find the complex and real roots for x^4-3x^2+2=0

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  1. 23 June, 18:33
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    X^4 - 3x^2 + 2 = 0

    (x^2 - 2) (x^2 - 1) = 0

    so either x^2 - 2 = 0 or x^2 - 1 = 0

    so x^2 = 2 or x^2 = 1

    so x = sqrt 2, - sqrt2, 1, - 1 Answer

    all the roots are real
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