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14 March, 22:22

The area of a certain rectangle is 288 yd2. the perimeter is 68 yd. what are the dimensions of the rectangle?

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  1. 15 March, 00:04
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    P = 2 (L + W)

    P = 68

    68 = 2 (L + W)

    68/2 = L + W

    34 = L + W

    34 - L = W

    A = L * W

    A = 288

    W = 34 - L

    288 = L (34 - L)

    288 = 34L - L^2

    L^2 - 34L + 288 = 0

    (L - 16) (L - 18)

    L - 16 = 0

    L = 16

    L - 18 = 0

    L = 18

    not exactly sure which (length or width), but one is 16 yds and one is 18 yds
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