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5 October, 10:19

In ∆ABC, if a = 8.75 centimeters, c = 4.26 centimeters, and m B = 87°, What is the length of b to two decimal places?

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Answers (2)
  1. 5 October, 11:28
    0
    Using law cosines:

    b^2 = a^2+c^2-2acCosb

    = 76.56+18.14-74.55 (0.05)

    = 94.7 - 3.9

    = 90.8

    b = sqrt 90.8

    b = 9.52
  2. 5 October, 12:59
    0
    You will need the law of cosines to solve it

    b2=a2+c2-2a*c*cos (B)

    just substitute your values
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