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Mathematics
Brenna Jackson
6 July, 09:20
What is the product? 3k/k+1*k^2-1/3k^3
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Byron Noble
6 July, 09:36
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We have [ (3k) x (k-1) x (k+1) ]/[3k^3x (k+1) ] = (k-1) / k^2;
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