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29 April, 03:09

An arrow is shot upward with a velocity of 64 feet per second. Using the formula h (t) = 64t-16t^2, how long after the arrow is released does it hit the ground?

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  1. 29 April, 07:00
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    It hits the ground when h (t) = 0

    -16t^2+64t=0 factor

    -16t (t-4) = 0, we know t>0 so

    t=4 seconds.
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