A student constructs a frequency distribution where the frequency of the first class is 8 and a corresponding histogram with the area of the bar in the first class is 80. The frequency for the second class is twice the frequency of the first class. In the histogram, the area of the bar corresponding to the second class is four times the area of the bar corresponding to the first class. What is the frequency of the second class and the area of the bar corresponding to the second class? 16, 320 8, 320 16, 160 8, 160

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21 August, 05:33

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Jayden Henry · Answer 1

Frequency of second class = 8*2 = 16. Area of bar for second class = 4*80 = 320

Its the first choice