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9 December, 06:19

One number is 16 more than a second number. The sum of the first number and twice the second number is 139. What is the answer?

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  1. 9 December, 08:00
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    Answer first number = 57 second number = 41

    x = 16 + y

    x + 2y = 139

    16 + y + 2y = 139

    16 + 3y = 139

    16-16 + 3y = 139-16

    3y = 123

    3/3y = 123/3

    y = 41

    x = 16+y

    x = 16+41

    x = 57
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