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8 November, 20:44

Solve for b 2 in A = h (b 1+b 2), if A = 16, h = 4, and b 1 = 3.

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  1. 8 November, 21:07
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    A = h (b1 + b2) ... when A = 16, h = 4, and b1 = 3

    now we sub

    16 = 4 (3 + b2)

    16/4 = 3 + b2

    4 = 3 + b2

    4 - 3 = b2

    1 = b2 <===
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