Ask Question
31 August, 13:10

6=2 (w-4)

and different problem

(2n-8) (-2) = - 24

and this problem

(2z+6) (3) = 33 and this one last one - 4 (-2b-7) = 44

+5
Answers (1)
  1. 31 August, 16:40
    0
    1) 6=2 (w-4)

    Divide both sides by 2.

    3=w-4

    Add 4 to both sides.

    7=w

    2) (2n-8) (-2) = - 24

    Divide both sides by - 2.

    2n-8=12

    Add 8 to both sides.

    2n=20

    Divide both sides by 2.

    n=10

    3) (2z+6) (3) = 33

    Divide both sides by 3.

    2z+6=11

    Subtract 6 from both sides.

    2z=5

    Divide both sides by 2.

    z = 2.5

    4) - 4 (-2b-7) = 44

    Divide both sides by - 4.

    -2b-7=-11

    Add 7 to both sides.

    -2b=-4

    Divde both sides by - 2.

    b=2
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “6=2 (w-4) and different problem (2n-8) (-2) = - 24 and this problem (2z+6) (3) = 33 and this one last one - 4 (-2b-7) = 44 ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers