Joseph is building a clone using modeling clay. The cone has a radius of 6 cm and a height of 12 cm Joseph adds additional clay keeping the radius the same until the cone reaches a height of 18 cm how much clay did Joseph add

So we want to know how much clay did Joseph add after he built the cone. So the formula for the volume of the cone is V = (1/3) * pi*r^2*h where r is the radius and h is height. We know h1=12cm and r1=6cm, r2=6cm and h2=18 cm. So to get the amount of added clay Va we simply subtract the volume of the clay of the first cone V1 from the volume of the second cone V2: Vd=V2-V1 = (1/3) * pi * (r1^2) * h1 - (1/3) + pi * (r2^2) * h2. Va=678.24 cm^3-452.39 cm^3 = 266.08 cm^3.

V2: Vd=V2-V1 = (1/3) * pi * (r1^2) * h1 - (1/3) + pi * (r2^2) * h2. Va=678.24 cm^3-452.39 cm^3 = 266.08 cm^3.