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7 June, 16:52

What is the solution of the equation 3^5 sqrt (x+2) ^3+3=27?

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Answers (2)
  1. 7 June, 17:11
    0
    3^5) (x + 2) ^ (3/2) + 3 = 27

    (x + 2) ^ (3/2) = 24 / 243

    x + 2 = [ 24 / 243 ]^ (2/3)

    x + 2 = [ 8 / 81 ]^ (2/3)

    x = [ 4 / 81^ (2/3) ] - 2 = - 1.786

    the answer is x=-1.786
  2. 7 June, 18:42
    0
    We rewrite the function:

    (3 ^ 5) * (sqrt (x + 2) ^ 3 + 3) = 27

    (3 ^ 5) * (sqrt (x + 2) ^ 3) = 27-3

    (3 ^ 5) * (sqrt (x + 2) ^ 3) = 24

    (3 ^ 4) * (sqrt (x + 2) ^ 3) = 8

    ((3 ^ 4) * (sqrt (x + 2) ^ 3)) ^ 2 = (8) ^ 2

    (3 ^ 8) * (x + 2) ^ 3 = 64

    ((3 ^ 8) * (x + 2) ^ 3) ^ (1/3) = (64) ^ (1/3)

    (3 ^ (8/3)) * (x + 2) = 4

    (x + 2) = 4 * (3 ^ (3/8))

    x = 4 * (3 ^ (3/8)) - 2

    Answer:

    the solution of the equation 3 ^ 5 sqrt (x + 2) ^ 3 + 3 = 27 is

    x = 4 * (3 ^ (3/8)) - 2
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