How many real number solutions does - 2x^2+8x-5=0

Use discriminant

for

ax²+bx+c=0

the discriminant is b²-4ac

if the discriminant is

1. less than 0, then no real number solutions

2. equal to 0, then there is 1 real number solution

3. greater than 0, then there are 2 real number solutions

-2x²+8x-5=0

a=-2

b=8

c=-5

b²-4ac=8²-4 (-2) (-5) = 64-40=24>0

2 real number solutions