What are the factors of the following quadratic equation 12=x^2-x

Question

Mathematics

Angie Landry

14 May, 00:35

What are the factors of the following quadratic equation 12=x^2-x

+4

Answers (1)

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Dunn · Answer 1

12 = x² - x

12 - 12 = x² - x - 12

0 = x² - x - 12

x² - x - 12 = 0

x = - (-1) + / - √ ((-1) ² - 4 (1) (-12))

2 (1)

x = 1 + / - √ (1 + 48)

2

x = 1 + / - √ (49)

2

x = 1 + / - 7

2

x = 0.5 + / - 3.5

x = 0.5 + 3.5 x = 0.5 - 3.5

x = 4 x = - 3