The length of a particular rectangle is 4 greater than the width of the rectangle. If the perimeter of the rectangle is 16, what is the area of the rectangle?

2l+2w=perimeter < = equation for perimeter

w+4=l <=length is 4 greater than width

2w+2 (w+4) = 24 < = plug in the l in the first equation with the second equation

2w+2w+8=24 < = solve the equation

4w=16

w=4

and, since

w+4=l < = length is 4 greater than width

then l=4+4

l=8