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20 December, 05:30

In how many ways can a 2-person committee be chosen from a group of 5 people (where the order in which we choose the 2 people doesn't matter) ?

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  1. 20 December, 06:03
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    If the order does not matter, then this is a combinations question. The number ways is calculated by

    ₅C₂ = 5!/[ (5-2) ! * 2! ] = 10

    There are 10 ways.
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