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Madison Salas
21 January, 23:58
Simplify log (x2-y2) - log (x-y) =
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Tanya Melendez
22 January, 00:28
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Remember:
log A - log B=log (A/B)
(a ²-b²) = (a+b) (a-b).
Therefore
log (x²-y²) - log (x-y) = log[ (x²-y²) / (x-y) ] = log[ (x+y) (x-y) / (x-y) ]=log (x+y)
Answer: log (x²-y²) - log (x-y) = log (x+y)
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Cesar Mcconnell
22 January, 01:16
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Using the law of logarithm. LogA - LogB = Log (A/B)
log (x²-y²) - log (x-y) = log ((x²-y²) / (x-y))
Note by difference of two squares, (x²-y²) = (x-y) (x+y)
Simplifying (x²-y²) / (x-y) = (x-y) (x+y) / (x-y) = (x+y)
Therefore log (x²-y²) - log (x-y) = log ((x²-y²) / (x-y)) = log ((x-y) (x+y) / (x-y)) = log (x+y)
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