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3 June, 17:55

A church has 10 bells in its bell tower. before each church service 3 bells are rung in sequence. no bell is rung more than once. how many sequences are there?

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  1. 3 June, 19:21
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    To solve this problem you must apply the proccedure shown below:

    1. You must apply the following Permutation formula:

    nPr=n! / (n-r) !

    Where n=8 and r=3

    2. Therefore, you have:

    n!=8!=8x7x6x5x4x3x2x1=40320

    (n-r) ! = (8-3) !=5!=5x4x3x2x1=120

    3. Then, when you substitute this values into the formula shown above, you obtain:

    nPr=n! / (n-r) !

    nPr=40320/120=336

    4. Therefore, as you can see, the answer is: 336
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