The absolute value function g (x) = |x + 7| - 4 is translated 5 units right and 2 units up to become g′ (x). The quadratic function f (x), graphed below, is also moved 5 units right and 2 units up to become f′ (x). Which of these two transformed functions has a range of y ≤ - 2 and what is the vertex of this transformed function?

g′ (x) has a range of y ≤ - 2 and its vertex is at (-2, - 2).

g′ (x) has a range of y ≤ - 2 and its vertex is at (2, - 2).

f′ (x) has a range of y ≤ - 2 and its vertex is at (3, - 2).

f′ (x) has a range of y ≤ - 2 and its vertex is at (-7, - 6).

Question

Quintin Powell

12 February, 01:20

+4

Answers (2)

Know the Answer?

Xiomara Walsh · Answer 1

I think its C, if I'm being quite honest its kind of confusing for me too. Sorry

Andreas Solis · Answer 2

Andreas Solis 12 February, 05:00

0

The correct answer is C.