Ask Question
17 September, 07:00

The population of a city is growing at an average rate of 3% per year. In 1990, the population was 45000

+2
Answers (2)
  1. 17 September, 07:37
    0
    P (y) = 450000 (1.03) ^ (y-1990)
  2. 17 September, 07:52
    0
    A. N (y) = 45,000*1.03^ (y-1990)

    N (y) = population in year y,

    45,000 = poppulation in 1990,

    1.03 = yearly growth factor,

    y = year y

    b. 2,007-1,990=17 years

    N (17) = 45,000*1.03^ (17) = 74,378.14

    c. 2N=N*1.03^ t

    2=1.03^t

    t=log (2) : log (1.03) = 23.4

    23.4+1,990=2,013.4

    d. 2 = (1+r) ^10

    r=2^ (1/10) - 1) * 100=7.18%
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “The population of a city is growing at an average rate of 3% per year. In 1990, the population was 45000 ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers