Ask Question
15 April, 22:09

Each day, a computer company produces 20 more laptops computers than desktop computers. On a certain day, 5% of the laptop computers and 7% of the desktop computers were found to be defective. If the total number of desktop and laptop computers that were found to be defective that day was 16, how many laptop computers did the computer company make that day?

+2
Answers (2)
  1. 16 April, 00:19
    0
    Let x be the no. of laptop computers make that day

    20 more laptops computers than desktop computers

    so no. of desktop computers = x-20

    5% of the laptop computers and 7% of the desktop computers

    = 0.05x + 0.07 (x-20)

    = 0.05x + 0.07x - 1.4

    = 0.12x - 1.4

    which equal to 16

    so 0.12x-1.4 = 16

    0.12x = 17.4

    x=145

    so the company builds 145 laptop computers that day
  2. 16 April, 01:25
    0
    l: laptop, d: desktop

    d = l-20

    (5l + 7d) / 100 = 16

    5l + 7l - 140 = 1600

    12l = 1740

    l = 145
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Each day, a computer company produces 20 more laptops computers than desktop computers. On a certain day, 5% of the laptop computers and 7% ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers