Ask Question
16 November, 12:02

A rectangle has a length five more than twice the width. If the perimeter is 22 units find the width and length

+1
Answers (1)
  1. 16 November, 12:37
    0
    Set the following: Length = L Width = W

    The length is twice the width: L = 2*W or: W = L/2

    Perimeter: P = 60ft = 2*L + 2*W

    Substituting L for W in the perimeter equation gives:

    P = 60ft = 2*L + 2 * (L/2) = 2*L + L = 3L

    L = 60ft/3 = 20ft W=L/2=20ft/2=10ft

    Verify result: Perimeter = P = 60ft = 2L + 2W = 2*20ft + 2*10ft = 40ft+20ft = 60ft

    The area of the rectangular is: Area = A = Length*Width = L*W = 20ft*10ft = 200 (ft) ^2

    -Rosie
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A rectangle has a length five more than twice the width. If the perimeter is 22 units find the width and length ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers