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8 September, 22:54

E bisects DF, DE = 5y, and EF = 13y-8. Find DE, EF, and DF

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  1. 9 September, 00:33
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    It bisects so DE=EF

    DE=5y

    EF=13y-8

    so

    5y=13y-8

    minus 13y both sides

    -8y=-8

    divide both sides by - 8

    y=1

    DE=5y=5 (1) = 5

    DE=EF=5

    DF=DE+EF=5+5=10

    DE=5

    EF=5

    DF=10
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