Ask Question
3 May, 04:40

Find the zero of f (x) = x^5-12x^2+32x

+1
Answers (1)
  1. 3 May, 05:38
    0
    The zeroes of f (x) = x^5-12x^2+32x can be found by factoring,

    f (x) = x^5-12x^2+32x = (x-8) (x-4)

    By the zero product theorem, (x-8) = 0 or (x-4) = 0 which means

    x=8 or x=4.

    So the zeroes of f (x) are S={4,8}
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Find the zero of f (x) = x^5-12x^2+32x ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers