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7 October, 23:26

During a particular baseball season, a team averaged 41,602 fans per home game. suppose attendance during the season follows the normal probability distribution with a standard deviation of 9,440 per game. what is the probability that a randomly selected game during the season had an attendance greater than 50,000 people?

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  1. 8 October, 03:26
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    Given:

    μ = 41,602, the mean

    σ = 9,440, the standard deviation.

    For the random variable x = 50,000, the z-score is

    z = (x - μ) / ο = (50,000 - 41,602) / 9,440 = 0.8896

    From standard tables, obtain

    P (x > 50,000) = 0.08132 or 81.32%

    Answer: 0.8132
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