In a population, 93% of the people are right-handed, and 7% of the people are left-handed. In each of the last 100 days, 1 person in the population has been randomly stopped on the street, For the first 93 days, the person stopped was right-handed, and for the last 7 days, the person stopped was left-handed. If the same person is allowed to be stopped on more than 1 day, what is the probability that the next person stopped will be right-handed?

Question

Mathematics

Tyshawn Swanson

29 September, 09:34

In a population, 93% of the people are right-handed, and 7% of the people are left-handed. In each of the last 100 days, 1 person in the population has been randomly stopped on the street, For the first 93 days, the person stopped was right-handed, and for the last 7 days, the person stopped was left-handed. If the same person is allowed to be stopped on more than 1 day, what is the probability that the next person stopped will be right-handed?

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Aspen Newton · Answer 1

93% because you completed the original set of 100% with the 93/7 day. You can practically restart the count and have again a 93% chance, as you originally had.