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25 February, 18:37

If sinX = 0.6, and X is in Quadrant II, then what is the value of cosX?

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  1. 25 February, 20:25
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    To calculate for cos X given that sin X=0.6 and is in Quadrant we proceed as follows:

    sin X=0.6

    Thus implies that:

    x=arcsin 0.6

    x=36.97

    given that X is in the Quadrant ii then the value of x will be:

    180-36.97

    =143.13

    hence cos X will be:

    cos X=cos 143.13

    cos X=-0.8
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