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13 January, 10:24

Conjugate of 8+4i ... ?

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Answers (2)
  1. 13 January, 10:54
    0
    The conjugate of any complex number in the form

    α + βi

    is

    α - βi

    So the conjugate of

    8 + 4i

    is

    8 - 4i
  2. 13 January, 11:42
    0
    8 + 4i * 8 - 4i / 8 - 4i

    64 - 16i^2 / 8 - 4i

    64 - 16 ( - 1) / 8 - 4i

    64 + 16 / 8 - 4i

    80 / 8 - 4i

    10 - 20i
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