What is the probability that a leap year selected at random will contain either 53 thursdays or 53 fridays?

There are 366 days in a leap year

In a week there are 7 days, so total no of days = 7*52=364 days.

Here 52 represents number of weeks.

Now last two days can be combination of two days say like Monday and Tuesday or Tuesday and Wednesday and so on.

So in total 7 combinations are possible.

Out of there can be 3 combinations containing Thursday or Friday.

Hence, the probability is 3/7.

Hence the answer is 3/7