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7 October, 09:52

Determine for what values of x and y are the following equalities always true.

(k+1) x - (2k+3) y-3k-5=0

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  1. 7 October, 13:36
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    (k+1) x - (2k+3) y-3k-5=0

    kx + x - 2ky - 3y - 3k - 5 = 0

    (x - 2y) k + (x - 3y) = 3k + 5

    therefore

    x - 2y = 3

    x - 3y = 5

    Subtract 2 equations

    y = - 2

    x = - 1
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