The sum of the least and greatest of the three consecutive odd integers is 114. What is the middle (second) of the three integers?

An odd number is represented always as 2n+1 or 2n-1, where n is an integer:

So, 3 consecutive ODD number are : 2n+1, 2n+3 and 2n+5

2n+1 + 2n + 5 = 114 → 4n + 6 = 114 → 4n = 108 and n = 27. Then the

1st odd is 2n+1 = 55

2nd consecutive odd 2n+3 = 57

3rd consecutive odd 2n+5 = 59