X2=12x-5 by completing scquare. which is the solutions set of the equation

X²=12x-5

minus 12x both sides

x²-12x=-5

take 1/2 of the linear confident and square it

-12/2=-6, (-6) ²=36

add that to both sides

x²-12x+36=-5+36

factor perfect square

(x-6) ²=31

sqrt both sides, remember to take positive and negative roots

x-6=+/-√31

x=6+/-√31

the solutions are 6+√31 and 6-√31