A ball is dropped from a height of 64 feet. Its height, in feet, can be modeled by the function h (t) = - 16t square + 64, where t is the time in seconds since the ball was dropped. After how many seconds will the ball hit the ground?

Question

Caroline Brennan

20 September, 16:27

+4

Answers (1)

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Mckenna Ferguson · Answer 1

T has to be bigger than 0

the ball hit the ground so h (t) = 0

-16t^ (2) + 64 = 0 - > 16t^2 = 64 - > t^2 = 4 - > t = 2s