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2 April, 09:03

What is the domain and derivative of f (x) = ln (2xsqrt (2+x)) ?

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  1. 2 April, 12:33
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    For domain 2x sqrt (2+x) >0

    x>0,2+x>0, x>-2 combining

    we get x>2

    f' (x) = [1/{2x sqrt (2+x) }][{2x / (2 sqrt (2+x)) }+2 sqrt (2+x) ]
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