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Mathematics
Armani Rush
15 September, 19:16
Verify (tanx-cotx) / sinxcosx = sec^2x-csc^2x
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Zion Singleton
15 September, 21:49
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Tan = sin/cos
cot = cos/sin
sec = (1/cos) ^2
csc = (1/sin) ^2
((sinx/cosx) - (cosx/sinx)) / cosxsinx
now multiply cosxsinx into the denominator so you get
(sinx/cos^2xsinx) - (cosx/sin^2xcosx)
the numerator and the denominator cancels so you have
(1/cos^2x) - (1/sin^2x) which is the same as sec^2x-csc^2x
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