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22 March, 22:20

What value should be added to both sides of the equation X2 + 12 X + 6 equals - 5 to solve the question by completing the square

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  1. 22 March, 22:43
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    X^2 + 12x + 6 = - 5

    x^2 + 12x = - 5 - 6

    x^2 + 12x = - 11

    x^2 + 12x + 36 = - 11 + 36 ... u add 36 to both sides <=

    (x + 6) ^2 = 25

    x + 6 = (+-) sqrt 25

    x + 6 = (+-) 5

    x = - 6 (+-) 5

    x = - 6 + 5

    x = - 1

    x = - 6 - 5

    x = - 11

    solutions are : x = - 1 or x = - 11

    ur answer : add 36 to both sides ... ur x term is 12, take half of ur x term, which gives u 6, then u square it, which gives u 36 ... and add that to both sides
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