Line j is perpendicular to the line with the given equation and the line j passes through p. write an equation of line j

Y=3/5x+2

P (5,1)

Note: I know the answer but I don't know the steps

Using the slope intercept formula, we can see that the slope of line p is 3/5. Since line j is perpendicular to line p it must have a slope that is the negative reciprocal (-5/3). Using the formula we can find the answer. j:y-1=-5/3 (x-5)

Doing some math we get:5x+3y=28