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7 December, 12:10

Given that

g (x) = 3x2+2x+5

find each of the following.

a)

g (-6)

b)

g (p+2)

+3
Answers (2)
  1. 7 December, 12:48
    0
    A.

    sub - 6 for x

    g (-6) = 3 (-6) ^2+2 (-6) + 5

    g (-6) = 3 (36) - 12+5

    g (-6) = 108-7

    g (-6) = 101

    b.

    sub p+2 for x

    g (p+2) = 3 (p+2) ^2+2 (p+2) + 5

    g (p+2) = 3 (p^2+4p+4) + 2p+4+5

    g (p+2) = 3p^2+12p+12+2p+9

    g (p+2) = 3p^2+14p+21
  2. 7 December, 14:23
    0
    A) Substitute - 6 for where x is in the expression ...

    g (-6) = 3 (-6) ^2 + 2 (-6) + 5

    g (-6) = 3 (36) + 2 (-6) + 5

    g (-6) = 108 + 2 (-6) + 5

    g (-6) = 108 - 12 + 5

    g (-6) = 96 + 5

    g (-6) = 101

    b) Substitute (p + 2) into where x is ...

    g (p + 2) = 3 (p + 2) ^2 + 2 (p + 2) + 5

    g (p + 2) = 3 (p + 2) (p + 2) + 2 (p + 2) + 5

    g (p + 2) = 3 (p^2 + 4p + 4) + 2 (p + 2) + 5

    g (p + 2) = 3p^2 + 12p + 12 + 2 (p + 2) + 5

    g (p + 2) = 3p^2 + 12p + 12 + 2p + 4 + 5

    g (p + 2) = 3p^2 + 14p + 21
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