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5 January, 12:11

If dy/dx = y cos x and y = 3 when x = 0, then y = ... ? Here are the answer choices

a) e^ (sinx) + 2

b) e^ (sinx) + 3

c) sin x + 3

d) sin x + 3e^x

e) 3e^ (sinx)

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Answers (1)
  1. 5 January, 13:42
    0
    Dy/dx = y cos x

    y = Ae^sin (x)

    y (0) = Ae^sin (0) = A = 3

    A = 3

    Therefore, y = 3e^ (sinx)
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