Ask Question
20 February, 08:30

Kara is 18 years younger than Joseph. Twelve years ago, Joseph was 4 times as old as Kara. Find their present ages.

+5
Answers (2)
  1. 20 February, 10:44
    0
    Let us call X Kara's age and Y Joseph's.

    We know that

    X=Y-18

    Y-12=4 (X-12)

    We can deduce from the second that

    Y-12=4X-48

    Y=4X-36

    So if you replace Y in the first equation you get:

    X = (4X-36) - 18

    X=4X-54

    3X=54

    X=18

    so we can deduce that 18=Y-18 which means that Y=36

    Kara is 18

    Joseph is 36
  2. 20 February, 10:47
    0
    To solve this, first you need to jump back the clock. so 18 minus 12 is 6. scince at that time joseph was 4 times older, 6 times 4 is 24. add that to 12 and you get 36. but we need to check our work. if 36 minus 18 isint 18 then we screwed up. but, we didnt. so now, Kara is 18 years old and Joseph is 36 years old.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Kara is 18 years younger than Joseph. Twelve years ago, Joseph was 4 times as old as Kara. Find their present ages. ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers