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6 August, 10:40

An object in shm oscillates with a period of 4.0s and an amplitude of 11 cm. part a how long does the object take to move from x = 0.0 cm to x = 6.5 cm.

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  1. 6 August, 14:29
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    If the Amplitud is 11*2=22cm and the wave was in shm then we can get the wavelength as 11*2=22s.

    From the wave equation,

    v=fλ Where v⇒speed

    f⇒frequency and

    λ⇒Wavelength

    And we know that;

    f=1/T

    f = 1/4 = 0.25 Hz

    ∴v = 0.25 * 22 = 5.5 cm/s

    Since we know know the speed of the object we can get its time it takes from (0-6.5) cm.

    v = fλ = λ/T

    ∴T = λ/v

    = 6.5/5.5

    = 1 2/11

    = 1.181818s

    The time taken for the object to move from x = 0.0 cm to x = 6.5 cm is 1.181818s
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