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22 September, 16:09

What are the roots of the polynomial equation x^3-6x = 3x^2-8? Use a graphing calculator and a system of equations.

-40, - 4, 5

-5, 4, 40

-4, - 1, 2

-2, 1, 4

+4
Answers (2)
  1. 22 September, 16:58
    0
    x^3 - 6x = 3x^2 - 8

    x^3 - 3x^2 - 6x = - 8

    x^3 - 3x^2 - 6x + 8 = 0

    now factor:

    (x-4) (x^2+x-2) = 0

    (x-4) (x-1) (x+2) = 0

    the roots are 4, 1, - 2

    answer is the last one
  2. 22 September, 17:45
    0
    Given the polynomial equation x^3 - 6x = 3x^2 - 8. Which can be simplified into (x^3) - 3 (x^2) - 6x + 8 = 0. The roots of the given equation are x = - 2, x = 1 and x = 4. The order of equation also represents the number of roots of the equation given. Since the highest exponent is 3, there also 3 roots. So the answer is D. 2 - 2, 1, 4
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