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2 June, 17:59

Which equation correctly solves for h, the x-coordinate of the vertex of a quadratic function, when starting with the equation for the vertex form of a parabola?

h = x + a-yk

h = x + a-ky

h = x + y-ka

h = x + y+ka

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Answers (1)
  1. 2 June, 20:05
    0
    Im pretty sure its h=x+y-ka
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